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Calculating the area of an ellipse is easy when you know the measurements of the major radius and minor radius.
Calculating the Area
Find the major radius of the ellipse. This is the distance from the center of the ellipse to the farthest edge of the ellipse. Think of this as the radius of the "fat" part of the ellipse. Measure it or find it labeled in your diagram. We'll call this value a. You can call this the "semi-major axis" instead.
Find the minor radius. As you might have guessed, the minor radius measures the distance from the center to the closest point on the edge. Call this measurement b. This is at a 90º right angle to the major radius, but you don't need to measure any angles to solve this problem. You can call this the "semi-minor axis."
Multiply by pi. The area of the ellipse is a x b x π. Since you're multiplying two units of length together, your answer will be in units squared. For example, if an ellipse has a major radius of 5 units and a minor radius of 3 units, the area of the ellipse is 3 x 5 x π, or about 47 square units. If you don't have a calculator, or if your calculator doesn't have a π symbol, use "3.14" instead.
Understanding Why it Works
Think of the area of a circle. You might remember that the area of a circle equals πr, which is the same as π x r x r. What if we tried to find the area of a circle as though it were an ellipse? We would measure the radius in one direction: r. Measure it at right angles: also r. Plug it into the ellipse area formula: π x r x r! As it turns out, a circle is just a specific type of ellipse.
Picture a circle being squashed. Imagine a circle being squeezed into an ellipse shape. As it's squeezed more and more, one radius gets shorter and the other gets longer. The area stays the same, since nothing's leaving the circle. As long as we use both radii in our equation, the "squashing" and the "flattening" will cancel each other out, and we'll still have the right answer.
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